We are given two sentences A and B. (A sentence is a string of space separated words. Each word consists only of lowercase letters.)
A word is uncommon if it appears exactly once in one of the sentences, and does not appear in the other sentence.
Return a list of all uncommon words.
You may return the list in any order.
Example 1:
Input: A = "this apple is sweet", B = "this apple is sour"
Output: ["sweet","sour"]Example 2:
Input: A = "apple apple", B = "banana"
Output: ["banana"]Note:
- 0 <= A.length <= 200
- 0 <= B.length <= 200
- A and B both contain only spaces and lowercase letters.
class Solution: def uncommonFromSentences(self, A, B): """ :type A: str :type B: str :rtype: List[str] """ dicta = {} dictb = {} res = [] for i in A.split(' '): if i not in dicta: dicta[i] = 1 else: dicta[i] += 1 for i in B.split(' '): if i not in dictb: dictb[i] = 1 else: dictb[i] += 1 for key,value in dicta.items(): if value==1 and key not in dictb: res.append(key) for key,value in dictb.items(): if value==1 and key not in dicta: res.append(key) return res